As in the previous Lectures, we consider a filtered probability space on which is defined a Brownian motion
, and we assume that
is the usual completion of the natural filtration of
. Our goal is here to write an orthogonal decomposition of the space
that is particularly suited to the study of the space
. For simplicity of the exposition, we restrict ourselves to the case where the Brownian motion
is one-dimensional.
In the sequel, for , we denote by
the simplex
and if
,
The set
is called the space of Wiener chaos of order . By convention the set of constant random variables shall be denoted by
.
By using the Itō’s isometry, we readily compute that
As a consequence, the spaces are orthogonal in
. It is easily seen that
is the closure of the linear span of the family
where for , we denoted by
the map
such that
. It turns out that
can be computed by using Hermite polynomials. The Hermite polynomial of order
is defined as
By the very definition of , we see that for every
,
Lemma. If then
Proof. On one hand, we have for ,
On the other hand, for , let us consider
From Itō’s formula, we have
By iterating the previous linear relation, we easily obtain that for every ,
We conclude,
As we pointed it out, for , the spaces
and
are othogonal. We have the following orthogonal decomposition of
:
Theorem.[Wiener chaos expansion]
Proof. As a by-product of the previous proof, we easily obtain that for ,
where the convergence of the series is almost sure but also in . Therefore, if
is orthogonal to
, then
is orthogonal to every
,
. This implies that
As we are going to see, the space or more generally
is easy to describe by using the Wiener chaos expansion. The keypoint is the following proposition:
Proposition. Let , then
and
where for
,
Proof. Let . We have
Thus is a smooth cylindric functional and
It is easy to see that , therefore we have
As a consequence, we compute that We now observe that
is the closure in
of the linear span of the family
to conclude the proof of the proposition
We can finally turn to the description of using the chaos decomposition:
Theorem. Let and let
be the chaotic decomposition of . Then
if and only if
and in that case,
Proof. It is a consequence of the fact that for ,
.
An immediate but useful corollary of the previous theorem is the following result:
Corollary. Let be a sequence in
that converges to
in
and such that
Then, .
Exercise. Let and let
be the chaotic decomposition of . Show that that
,
if and only if
Exercise. Let . Show that for
,
.
A typo on line constant instead of contant.
Thanks. I corrected