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The Lp theory of heat semigroups
Our goal, in this section, is to define, for 1 ≤ p ≤ +∞, Pt on Lp := Lp(X,μ). This may be done in a natural way by using the Riesz-Thorin interpolation theorem that we recall below.
Theorem (Riesz-Thorin interpolation theorem)
Let 1 ≤ p0, p1, q0, q1 ≤ ∞, and θ ∈ (0,1). Define 1 ≤ p,q ≤ ∞ by
1/p = (1-θ)/p0 + θ/p1, 1/q = (1-θ)/q0 + θ/q1.
If T is a linear map such that
T : Lp0 → Lq0, ||T||Lp0→Lq0 = M0
T : Lp1 → Lq1, ||T||Lp1→Lq1 = M1,
then, for every f ∈ Lp0 ∩ Lp1,
||Tf||q ≤ M01-θM1θ ||f||p.
Hence T extends uniquely as a bounded map from Lp to Lq with
||T||Lp→Lq ≤ M01-θM1θ.
Remark The statement that T is a linear map such that
T : Lp0 → Lq0, ||T||Lp0→Lq0 = M0
T : Lp1 → Lq1, ||T||Lp1→Lq1 = M1
means that there exists a map T : Lp0 ∩ Lp1 → Lq0 ∩ Lq1 with
supf ∈ Lp0 ∩ Lp1 , ||f||p0 ≤ 1 ||Tf||q0 = M0
and
supf ∈ Lp0 ∩ Lp1 , ||f||p1 ≤ 1 ||Tf||q1 = M1.
In such a case, T can be uniquely extended to bounded linear maps T0 : Lp0 → Lq0 , T1 : Lp1 → Lq1. With a slight abuse of notation, these two maps are both denoted by T in the theorem.
Remark If f ∈ Lp0 ∩ Lp1 and p is defined by
1/p = (1-θ)/p0 + θ/p1,
then by Hölder’s inequality, f ∈ Lp and
||f||p ≤ ||f||p01-θ ||f||p1θ.
We now are in position to state the following theorem:
Theorem Let (Pt)t≥0 be a strongly continuous self-adjoint contraction Markovian semigroup on L2(X,μ). The space L1 ∩ L∞ is invariant under Pt and Pt may be extended from L1 ∩ L∞ to a contraction semigroup (Pt(p))t≥0 on Lp for all 1 ≤ p ≤ ∞: For f ∈ Lp,
||Ptf||Lp ≤ ||f||Lp.
These semigroups are consistent in the sense that for f ∈ Lp ∩ Lq,
Pt(p)f = Pt(q)f.
If f,g ∈ L1 ∩ L∞ which is a subset of L1 ∩ L∞, then,
|∫X (Ptf)g dμ| = |∫X f (Ptg) dμ| ≤ ||f||L1 ||Ptg||L∞ ≤ ||f||L1 ||g||L∞.
This implies
||Ptf||L1 ≤ ||f||L1.
The conclusion follows then from the Riesz-Thorin interpolation theorem.
Exercise Show that if f ∈ Lp and g ∈ Lq with 1/p + 1/q = 1 then,
∫ℝn f Pt(q) g dμ = ∫ℝn g Pt(p) f dμ.
Exercise
- Show that for each f ∈ L1, the L1-valued map t → Pt(1)f is continuous.
- Show that for each f ∈ Lp, 1 < p < 2, the Lp-valued map t → Pt(p)f is continuous.
- Finally, by using the reflexivity of Lp, show that for each f ∈ Lp and every p ≥ 1, the Lp-valued map t → Pt(p)f is continuous.
We mention, that in general, the L∞ valued map t → Pt(∞)f is not continuous.
Diffusion operators as generators of Dirichlet forms
Consider a diffusion operator
L = ∑i,j=1n σij(x) ∂2/∂xi∂xj + ∑i=1n bi(x) ∂/∂xi,
where bi and σij are continuous functions on ℝn and for every x ∈ ℝn, the matrix (σij(x))1 ≤ i,j ≤ n is a symmetric and non-negative matrix.
Assume that there is Borel measure μ on ℝn which is equivalent to the Lebesgue measure and that symmetrizes L in the sense that for every smooth and compactly supported functions f, g : ℝn → ℝ,
∫ℝn gLf dμ = ∫ℝn fLg dμ.
For instance, if one can write
Lf = -div(a ∇f),
where a is a smooth field of positive and symmetric matrices, then the Lebesgue measure symetrizes L. From a previous lemma the quadratic form
ℰ(f,g) = -∫ℝn g Lf dμ, f,g ∈ Cc∞(ℝn)
is closable. Let ℰ̄ denotes its closure in L2(ℝn,μ).
Proposition The quadratic form ℰ̄ is a Dirichlet form.
We need to prove that ℰ̄ is Markovian. It is enough to prove that if u ∈ ℱ = 𝒟(ℰ), then |u| ∈ ℱ with ℰ̄(|u|, |u|) ≤ ℰ̄(u,u) and that if u ∈ ℱ with u ≥ 0, then u ∧ 1 ∈ ℱ with ℰ̄(|u|,|u|) ≤ ℰ̄(u,u). We prove the first requirement, the second being established in a similar manner is let as an exercise to the reader.
Let u ∈ Cc∞(ℝn) and consider
ϕε(x) = (x2 + ε2)^{1/2}, ε > 0.
One can check that ϕε(u) → |u| in L2(ℝn,μ) and that ϕε(u) is a Cauchy sequence for the norm
||f||ℱ2 = ||f||2L2(ℝn,μ) + ℰ̄(f,f).
Since ℰ̄ is closed this implies that |u| ∈ ℱ and that ϕε(u) → |u| converges to u in the above norm.
Now, using chain rule we see that for every smooth function u ∈ Cc∞(ℝn),
Lϕε(u)(x) ≥ u(x)/(u(x)2 + ε2)^{1/2} Lu(x).
Multiplying by ϕε(u) and integrating we get
ℰ(ϕε(u), ϕε(u)) ≤ ℰ(u,u)
Taking the limit ε → 0 yields
ℰ̄(|u|, |u|) ≤ ℰ̄(u,u)
The above inequality extends then to all u ∈ ℱ by using the density of Cc∞(ℝn) in the || · ||ℱ norm and the closedness of ℰ.