In this lecture, we first quickly review what was done in the previous one. We then introduce the horizontal and vertical Laplacians and prove basic commutations results. We explain them the notion of Riemannian foliation. In the second part of the lecture we study the Heisenberg group and show how to compute its heat kernel.
Let
be a Riemannian submersion. If
we define its vertical gradient
as the projection of its gradient onto the vertical distribution and its horizontal gradient
as the projection of the gradient onto the horizontal distribution. We define then the vertical Laplacian
as the generator of the Dirichlet form

where
is the Riemannian volume measure on
. Similarly, we define the horizonal Laplacian
as the generator of the Dirichlet form

If
is a local orthonormal frame of basic vector fields and
a local orthonormal frame of the vertical distribution, then we have

and

where the adjoints are understood in
. Classically, we have

where
is the Levi-Civita connection. As a consequence, we obtain

where
denotes the horizontal part of the vector. In a similar way we obviously have

We can observe that the Laplace-Beltrami operator
of
can be written

It is worth noting that, in general,
is not the lift of the Laplace-Beltrami operator
on
. Indeed, let us denote by
the vector fields on
which are
-related to
.
We have

Since it is easy to check that
is
-related to
, we deduce that
lies above
, i.e. for every
,
, if and only if the vector

is vertical. This condition is equivalent to the fact that the mean curvature of each fiber is zero, or in other words that the fibers are minimal submanifolds of
. This happens for instance for submersions with totally geodesic fibers.
We also note that from Hormander’s theorem, the operator
is subelliptic if the horizontal distribution is bracket generating. Of course, the vertical Laplacian is never subelliptic because the vertical distribution is always integrable.
The following result, though simple, will turn out to be extremely useful in the sequel when dealing with curvature dimension estimates and functional inequalities.
Theorem: The Riemannian submersion
has totally geodesic fibers if and only if for every
,

Proof: If
is a local orthonormal frame of basic vector fields and
a local orthonormal frame of the vertical distribution, then we easily compute that
![\langle \nabla_{\mathcal{H}} f , \nabla_{\mathcal{H}} \| \nabla_{\mathcal{V}} f \|^2 \rangle-\langle \nabla_{\mathcal{V}} f , \nabla_{\mathcal{V}} \| \nabla_{\mathcal{H}} f \|^2 \rangle=2\sum_{i=1}^n \sum_{j=1}^m (X_i f) (Z_j f) ([X_i,Z_j] f).](https://s0.wp.com/latex.php?latex=%5Clangle+%5Cnabla_%7B%5Cmathcal%7BH%7D%7D+f+%2C+%5Cnabla_%7B%5Cmathcal%7BH%7D%7D+%5C%7C+%5Cnabla_%7B%5Cmathcal%7BV%7D%7D+f+%5C%7C%5E2+%5Crangle-%5Clangle+%5Cnabla_%7B%5Cmathcal%7BV%7D%7D+f+%2C+%5Cnabla_%7B%5Cmathcal%7BV%7D%7D+%5C%7C+%5Cnabla_%7B%5Cmathcal%7BH%7D%7D+f+%5C%7C%5E2+%5Crangle%3D2%5Csum_%7Bi%3D1%7D%5En+%5Csum_%7Bj%3D1%7D%5Em+%28X_i+f%29+%28Z_j+f%29+%28%5BX_i%2CZ_j%5D+f%29.&bg=ffffff&fg=333333&s=0&c=20201002)
As a consequence,

if and only if for every basic vector field
,
![\sum_{j=1}^m (Z_j f) ([X,Z_j] f)=0.](https://s0.wp.com/latex.php?latex=%5Csum_%7Bj%3D1%7D%5Em+%28Z_j+f%29+%28%5BX%2CZ_j%5D+f%29%3D0.&bg=ffffff&fg=333333&s=0&c=20201002)
This condition is equivalent to the fact that the flow generated by
induces an isometry between the fibers, and so from Hermann’s Theorem this is equivalent to the fact that the fibers are totally geodesic 
The second commutation result that characterizes totally geodesic submersions is due to Berard-Bergery and Bourguignon.
Theorem: The Riemannian submersion
has totally geodesic fibers if and only if any basic vector field
commutes with the vertical Laplacian
. In particular, if
has totally geodesic fibers, then for every
,

Proof. Assume that the submersion is totally geodesic. Let
be a basic vector field and
be the flow it generates. Since
induces an isometry between the fibers, we have

Differentiating at
yields
.
Conversely, assume that for every basic field
,
. Let
be a local orthonormal frame of basic vector fields and
be a local orthonormal frame of the vertical distribution. The second order part of the operator
must be zero. Given the expression of the vertical Laplacian, this implies
![\sum_{i=1}^m [X,Z_i] Z_i=0.](https://s0.wp.com/latex.php?latex=%5Csum_%7Bi%3D1%7D%5Em+%5BX%2CZ_i%5D+Z_i%3D0.&bg=ffffff&fg=333333&s=0&c=20201002)
So
leaves the symbol of
invariant which is the metric on the vertical distribution. This implies that the flow generated by
induces isometries between the fibers.
Finally, as we have seen, if the submersion is totally geodesic then in a local basic orthornomal frame

Since the vectors
are basic, from the previous result
commutes with

We now turn to the notion of Riemannian foliation.
In many interesting cases, we do not actually have a globally defined Riemannian sumersion but a Riemannian foliation.
Definition: Let
be a smooth and connected n+m dimensional manifold. A
-dimensional foliation
on
is defined by a maximal collection of pairs
of open subsets
of
and submersions
onto open subsets of
satisfying:
;
- If
, there exists a local diffeomorphism
of
such that
on
.
The maps
are called disintegrating maps of
. The connected components of the sets
,
, are called the plaques of the foliation. A foliation arises from an integrable sub-bundle of
, to be denoted by
and referred to as the vertical distribution. These are the vectors tangent to the leaves, the maximal integral sub-manifolds of
.
Foliations have been extensively studied and numerous books are devoted to them. We refer in particular to the book by Tondeur.
In the sequel, we shall only be interested in Riemannian foliations with bundle like metric.
Definition: Let
be a smooth and connected $mathbb n+m$ dimensional Riemannian manifold. A
-dimensional foliation
on
is said to be Riemannian with a bundle like metric if the disintegrating maps
are Riemannian submersions onto
with its given Riemannian structure. If moreover the leaves are totally geodesic sub-manifolds of
, then we say that the Riemannian foliation is totally geodesic with a bundle like metric.
Observe that if we have a Riemannian submersion
, then
is equipped with a Riemannian foliation with bundle like metric whose leaves are the fibers of the submersion. Of course, there are many Riemannian foliations with bundle like metric that do not come from a Riemannian submersion.
Since Riemannian foliations with a bundle like metric can locally be desribed by a Riemannian submersion, we can define a horizontal Laplacian
and a vertical Laplacian
. Observe that they commute on smooth functions if the foliation is totally geodesic. More generally all the local properties of a Riemannian submersion extend to Riemannian foliations.
In the second part of the lecture, we deal with model spaces.
One of the simplest non trivial Riemannian submersions with totally geodesic fibers and bracket generating horizontal distribution is associated to the Heisenberg group. The Heisenberg group is the set

endowed with the group law

The vector fields


and

form an orthonormal frame of left invariant vector fields for the left invariant metric on
. Note that the following commutations hold
![[X_i,Y_j]=2\delta_{ij} Z, \quad [X_i,Z]=[Y_i,Z]=0.](https://s0.wp.com/latex.php?latex=%5BX_i%2CY_j%5D%3D2%5Cdelta_%7Bij%7D+Z%2C+%5Cquad+%5BX_i%2CZ%5D%3D%5BY_i%2CZ%5D%3D0.&bg=ffffff&fg=333333&s=0&c=20201002)
The map

is then a Riemannian submersion with totally geodesic fibers. The horizontal Laplacian is the left invariant operator


and the vertical Laplacian is the left invariant operator

The horizontal distribution

is bracket generating at every point, so
is a subelliptic operator. The operator
is invariant by the action of the orthogonal group of
on the variables
. Introducing the variable
, we see then that the radial part of
is given by

This means that if
is a smooth map and
is the submersion
then

From this invariance property in order to study the heat kernel and fundamental solution of
at
it suffices to study the heat kernel and the fundamental solution of
at
.
We denote by
the heat kernel at 0 of
. It was first computed explicitly by Gaveau building on previous works by Paul Levy.
Proposition: For
and
,

Proof: Since
commutes with
, the idea is to use a Fourier transform in
. We see then that

where
is the fundamental solution at 0 of the parabolic partial differential equation

We thus want to compute the semigroup generated by the Schrodinger operator

The trick is now to observe that for every
,

where

The operator
turns out to be the radial part of the Ornstein-Uhlenbeck operator
whose heat kernel at 0 is a Gaussian density with mean 0 and variance
. This means that the heat kernel at 0 of
is given by

We conclude


The second simplest and geometrically relevant example is given by the celebrated Hopf fibration. Let us consider the odd dimensional unit sphere

There is an isometric group action of
on
which is defined by

The generator of this action shall be denoted by
. We thus have for every 

so that

The quotient space
is the projective complex space
and the projection map
is a Riemannian submersion with totally geodesic fibers isometric to
. The fibration

is called the Hopf fibration.
To study the geometry of the Hopf fibration, in particular the horizontal Laplacian
, it is convenient to introduce a set of coordinates that reflects the action of the isometry group of
on
.
Let
be the local inhomogeneous coordinates for
given by
, and
be the local fiber coordinate. i.e.,
parametrizes the complex lines passing through the north pole, while
determines a point on the line that is of unit distance from the north pole. More explicitly, these coordinates are given by the map

where
,
, and
. In these coordinates, it is clear that
and that the vertical Laplacian is

Our first goal is now to compute the horizontal Laplacian
. This operator is invariant by the action on the variables
of the group of isometries of
that fix the north pole of
(this group is
). Therefore the heat kernel at the north pole only depends on the variables
.
Proposition: The radial part of the horizontal Laplacian is the operator

Proof: The easiest route is to compute first the radial part of the Laplace-Beltrami operator
and then to use the formula

In our parametrization of
we have,

Therefore if
denotes the Riemannian distance based at the north pole, we have
and if
denotes the Riemannian distance based at the point with real coordinates
then we have
. The formula for the Laplace-Beltrami operator acting on functions depending on the Riemannian distance based at a point is well-known and we deduce from it that
acts on functions depending only on
as

In the variables
this last operator writes

This concludes the proof 